From the given pairs of compounds,in which wi | vedclass

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(C) The rate of $S_N2$ reaction depends on steric hindrance and the nature of the leaving group. $(a)$ $CH_3CH(CH_3)CH_2Br$ is a primary alkyl halide

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$CH_3COCH_2Cl$ and $CH_3CH_2Cl$

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(C) The rate of $S_N2$ reaction depends on steric hindrance and the nature of the leaving group. $(a)$ $CH_3CH(CH_3)CH_2Br$ is a primary alkyl halide with more steric hindrance than $CH_3CH_2CH_2CH_2Br$,so the second compound reacts faster. $(b)$ $I^-$ is a better leaving group than $Cl^-$,so $CH_3CH_2CH_2CH_2I$ reacts faster. $(c)$ $\alpha$-halocarbonyl compounds like $CH_3COCH_2Cl$ undergo $S_N2$ reactions much faster than simple alkyl halides like $CH_3CH_2Cl$ because the carbonyl group $(C=O)$ is electron-withdrawing and stabilizes the transition state through the overlap of its $\pi$ system with the p-orbitals of the transition state. $(d)$ $CH_3Br$ is less sterically hindered than $CH_3CH_2Br$,so $CH_3Br$ reacts faster. Therefore,the first compound reacts faster in option $(c)$.

From the given pairs of compounds,in which will the first compound undergo $S_N2$ reaction faster?

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